JSONSwiftSon Documentation
Welcome to the documentation for JSONSwiftSon, a lightweight JSON parsing library for Swift. JSONSwiftSon provides intuitive and efficient methods to parse and manipulate JSON data, allowing you to seamlessly work with JSON objects, arrays, and values in your Swift projects.
Key Features
- Simple and intuitive syntax
- Efficient JSON parsing and serialization
- Supports parsing JSON into Swift structs and classes
- Ability to extract values from nested JSON objects and arrays
- Convenient methods for manipulating JSON data
Installation
npm install json-swiftson
Usage
1. Parsing JSON
To parse a JSON string, use the `JSON.parse()` method:
let jsonString = "{\"name\":\"John\",\"age\":30,\"city\":\"New York\"}"
let jsonObject = JSON.parse(jsonString)
print(jsonObject)
2. Accessing JSON Values
You can easily access values from parsed JSON using key-value coding:
let name = jsonObject.name
let age = jsonObject.age
print("Name: \(name), Age: \(age)")
3. JSON Objects and Arrays
JSONSwiftSon provides methods to work with JSON objects and arrays:
// Accessing a JSON object
let user = jsonObject.user
let username = user["username"]
// Accessing a JSON array
let cities = jsonObject.cities
let firstCity = cities[0]
4. Manipulating JSON Data
You can update or add new values to parsed JSON:
// Update a value
jsonObject.age = 31
// Add a new value
jsonObject.email = "john@example.com"
print(jsonObject)
5. Serialization
To convert a JSON object back to a string, use the `JSON.stringify()` method:
let jsonStringUpdated = JSON.stringify(jsonObject)
print(jsonStringUpdated)
Conclusion
JSONSwiftSon simplifies the process of working with JSON data in Swift, providing a convenient and efficient way to parse, manipulate, and serialize JSON objects. It offers a simple syntax and useful methods, making it an ideal choice for Swift developers.